- Solving a system of linear equations using rref() -
reduced row echelon
form.
For example, to solve the system {2x - 3y = 4, x + y = 6}, follow the
steps below:
( Depending on the model, the key strokes may be slightly different.)
- Turn the power on and Clear everything on the display.
- [
] [ ] [ ] [ ] [ ] [ ]
(Assume that matrix A is selected for editing.)
- 2 [
] 3 [ ]
- [
] 2 [ ] [ 3 [ ] 4 [ ]
(Data from the first equation.)
- [
] 1 [ ] 1 [ ] 6 [ ]
(Data from the second equation)
- The TI-8x display should look like this
- [
] [ ] [ ] [ ] (11 times) [ ]
(Select the matrix operation rref() )
- [
] [ ] [ ]
(Select the matrix A.)
- [
] [ ]
- The above system is in reduced row echelon form. The solution of the system is:
x = 4.4
y = 1.6
- Exercise: Show that the rref of the matrix (B) of the system of linear equations
x + 2y = 3
4x + 5y = 6 is
|
|