- Solving a system of linear equations using rref() -
reduced row echelon
form.
For example, to solve the system {2x - 3y = 4, x + y = 6}, follow the
steps below:
( Depending on the model, the key strokes may be slightly different.)
- Turn the power on and Clear everything on the display.
- [] [] [] [] [] []
(Assume that matrix A is selected for editing.)
- 2 [] 3 []
- [] 2 [] [3 [] 4 []
(Data from the first equation.)
- [] 1 [] 1 [] 6 []
(Data from the second equation)
- The TI-8x display should look like this
- [] [] [] [] (11 times) []
(Select the matrix operation rref() )
- [] [] []
(Select the matrix A.)
- [] []
- The above system is in reduced row echelon form. The solution of the system is:
x = 4.4
y = 1.6
- Exercise: Show that the rref of the matrix (B) of the system of linear equations
x + 2y = 3
4x + 5y = 6 is
|
|